show that
sin θ-2 sin³θ/ 2 cos³θ- cos θ= tan θ
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L.H.S
sinA - 2sin^3A / 2cos^3A - cosA
= sinA ( 1 - 2sin^2A ) /( 2cos^2 A - 1 ) cosA
= sinA ( 1 - 2sin^2 A) / ( 2cos^2A - 1 ) cosA
= sinA cos2A / cos2A cosA
= tanA, R.H.S
●hope it helps ●
sinA - 2sin^3A / 2cos^3A - cosA
= sinA ( 1 - 2sin^2A ) /( 2cos^2 A - 1 ) cosA
= sinA ( 1 - 2sin^2 A) / ( 2cos^2A - 1 ) cosA
= sinA cos2A / cos2A cosA
= tanA, R.H.S
●hope it helps ●
mohammedfaizan258:
thanks
welcome
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