Question

show that sin (330) Cos (390) - sin(510) cos(570)​

Answer 1

Step-by-step explanation:

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Answer 2

cos2θ + 3 sin θ + 3 sin2θ = 0

1 – sin2θ + 3 sin θ + 3 sin2θ = 0

2 sin2θ + 3 sin θ + 1 = 0

2sin2θ + 2 sin θ + sin θ + 1 = 0

2 sin θ (sin θ +1 ) + 1 (sin θ + 1) = 0

(2 sin θ + 1) (sin θ + 1) = 0

2 sin θ + 1 = 0, sin θ + 1 = 0

sin θ = -½, sin θ = -1