Question

show that sin 35 sec 55 tan 40 tan 50 = 1​

Answer 1

Answer:

sin 35 sec 55 tan 40 tan 50

sin 35 *1/cos 55 *tan 40 * cot (90-50)

( as sec theta = 1/cos theta.

tan theta = cot(90-theta)

sin 35 * 1/sin(90-55) * tan 40 * cot 40

(cos theta = sin(90-theta)

sin 35 * 1/sin 35 * tan 40 * 1/tan 40

(as cot theta = 1/tan theta)

1 * 1 = 1

hence prved

Step-by-step explanation:

sin 35 and 1/ sin 35 cancelled out

tan 40 and 1/ tan 40 cancelled out