show that sin 35 sec 55 tan 40 tan 50 = 1
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Answer:
sin 35 sec 55 tan 40 tan 50
sin 35 *1/cos 55 *tan 40 * cot (90-50)
( as sec theta = 1/cos theta.
tan theta = cot(90-theta)
sin 35 * 1/sin(90-55) * tan 40 * cot 40
(cos theta = sin(90-theta)
sin 35 * 1/sin 35 * tan 40 * 1/tan 40
(as cot theta = 1/tan theta)
1 * 1 = 1
hence prved
Step-by-step explanation:
sin 35 and 1/ sin 35 cancelled out
tan 40 and 1/ tan 40 cancelled out
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