show that sin 3theta=sin theta(2 cos 2theta +1)
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Step-by-step explanation:
dear reader,
sin 3 theota= sin theota (2cos 2theota+1)
Take sin theota on the left hand side
sin 3 theota/sin theota =(2 cos 2 theota +1)
L.H.S
sin3 theota /sin theota
= (3sin theota-4 sin^3 theota)/sin theota
= (3sin theota/sin theota )-(4sin^3 theota/sin theota)
=3-4sin^2 theota
=3-4(1-cos^2 theota)
=3-4+4 cos^2 theota
= -1+2(2cos^2 theota)
= -1+2(cos 2 theota+1)
= -1+2 cos 2 theota +2
=2cos2 theota+1
=RHS
hence proved
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