show that: sin 42° sec 48° + cos 42° cosec 48° = 2
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constitution is a perfect fit for the first to
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LHS=sin42sec48+cos42cosec48
=sin42/cos48+cos42/sin48 (since secx=1/cosx and cosecx=1/sinx)
=sin42/cos(90-42)+cos42/sin(90-42)
=sin42/sin42+cos42/cos42. [Since cos(90-x)=sinx and sin(90-x)=cosx ]
=1+1
=2
= RHS
SINCE LHS=RHS
Therefore sin42sec48+cos42cosec48=2
Hence Proved
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