Question

Show that
sin 52° sin 38º- cos 52° cos 38°=0
$\sin(52) \sin(38) - \cos(52) \cos(38) = 0$
​

Answer 1

Answer:

sin52 cos 52 - cos 52 cos 52

1 - 1 ( sin theta + cos theta=1)

0

hence proved

LHS= RHS