Math, asked by rajeshsaraswat1234, 3 months ago

Show that
sin 52° sin 38º- cos 52° cos 38°=0
$\sin(52) \sin(38) - \cos(52) \cos(38) = 0$

Answers

Answered by Manishachowbe1502

0

Answer:

sin52 cos 52 - cos 52 cos 52

1 - 1 ( sin theta + cos theta=1)

0

hence proved

LHS= RHS

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