show that : sin 7+sin 5+sin 9+sin 3/
cos 7+cos cos 9+cos 3 = tan 6
Answers
Answered by
0
Answer:
LHS=
(cos7x+cos5x)+(cos9x+cos3x)
(sin7x+sin5x)+(sin9x+sin3x)
=
2cos6xcosx+2cos6xcos3x
2sin6xcosx+2sin6xcos3x
=
2cos6x(cosx+cos3x)
2sin6x(cosx+cos3x)
=tan6x=RHS
Step-by-step explanation:
please make me brainlist please
Similar questions