Question

Show that: sin 8 theta = 8 sin theta × cos theta × sin 2 theta × cos 2 theta

Answer 1

Let theta be A
sin 8A=sin 2×4A
=2 sin4A cos4A
=2 sin 2×2A cos 2×2A
=2. 2sin2A cos2A. 2 sinA cosA
=8 sinA cosA sin2A cos2A

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