Question

Show that sin (90 - 0) = cos e​

Answer 1

Sin (90+∅) = cos

( Ms binu sin (a+b) Sina cos b+ cos A sin B

sin (90 +0) = sin 90 cos ø+ cos 90=0

we know that [ sin 90=1] and [ cos 90= 0] then

sin [90+0]= cos +0= cos ø = Rhs

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