Question

show that (sin A + Cose C A)^2; (cosA + SecA)^2
7 + Tan" At Cot2A.​

Answer 1

$\huge\color{Black}\boxed{\colorbox{yellow}{꧁Answer꧂}}$

(sinA+cosecA)²+(cosA+secA)²

=sin²A+cos²A+2+cos²A+sec²A+2

=5+sec²A+cosec²A

=5+1+tan²A+1+cot²A

=7+tan²A+cot²A