Question

Show that ( sin θ + cos θ ) 2 = 1 + 2 sin θ cos θ.​

Answer 1

Step-by-step explanation:

LHS:-

( sin θ + cos θ )^2

This is in the form of (a+b)^2

Here , a= Sinθ and b = Cosθ

(a+b)^2 =a^2+2ab+b^2

( sin θ + cos θ ) ^2

=Sinθ^2 + 2Sinθcosθ +Cosθ^2

We know that Sinθ^2 +Cosθ^2=1

=>1+2Sinθcosθ

=RHS

LHS=RHS

(sinθ+cosθ)^2 = 1+2sinθcosθ.

Answer 2

Step-by-step explanation:

prove kare tho answer Aayyega