Show that ( sin θ + cos θ ) 2 = 1 + 2 sin θ cos θ.
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Answer:
LHS: (sin θ + cos θ)²
= sin²θ + cos²θ + 2 sin θ cos θ
= (sin²θ + cos²θ) + 2 sin θ cos θ
= 1 + 2 sin θ cos θ
= RHS
Hence, proved!
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