Math, asked by ahamedaman21, 9 months ago

Show that: (sinΘ + cosΘ)^2 + (sinΘ - cosΘ)^2 = 2

Answers

Answered by tennetiraj86

2

Answer:

answer for the given problem is given

Attachments:

Answered by deve11

2

Answer:

Let Θ=A.

Step-by-step explanation:

LHS= (sinA+ cosA)^2 + (sinA - cosA)^2

=sin²A+cos²A+2sinAcosA+sin²A+cos²A-2sinAcosA.

==1+2sinAcosA+1-2sinAcosA

[sin²A+cos²A=1

2sinAcosA cancels ]

=1+1=2.

=RHS.

Hence proved.

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