Math, asked by poonamtripathicnb, 1 year ago

show that sin / cosec -1 + cos / 1+sec = sin cos /sin - cos

Answers

Answered by omgavhane111
3

hello this is your answer

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Answered by amitnrw
6

LHS ≠ RHS for Sinx/(Cosecx - 1 )  + Cosx/(1 + secx)    = Sinx Cosx/(Sinx - Cosx) hence mistake in data

Step-by-step explanation:

Sinx/(Cosecx - 1 )  + Cosx/(1 + secx)    = Sinx Cosx/(Sinx - Cosx)

Lets take x = 30°

Sin30° = 1/2

Cosec30° = 2

Cos30° = √3 / 2

Sec30° = 2/√3

LHS = (1/2)/(2 - 1)   +  (√3 / 2)(1  + 2/√3)

= 1/2  + (3/2)/(√3 + 2)

= (1/2) (1  +  3/(√3 + 2))

= (1/2) ( 1   + 3 (2 - √3))

= (1/2)(7 - 3√3)

= (7 - 3√3)/2

RHS

= (1/2)(√3 /2)/ (1/2 -√3 /2)

= (√3 /2)/ (1 - √3)

=  (√3 /2)(√3 + 1)/(-2)

=  -(3 + √3)/4

LHS ≠ RHS

Hence mistake in given data

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