Question

Show that sin teta+sin^2(teta+60°)+sin’ (teta-60°) =3/2​

Answer 1

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Answer 2

Answer:

3/2

Step-by-step explanation:

sin

2

θ+sin

2

(60

∘

+θ)+sin

2

(60

∘

−θ)=sin

2

θ+

2

1

(1−cos(120

∘

+2θ))+

2

1

(1−cos(120

∘

−2θ))

=sin

2

θ+1−

2

1

(cos(120

∘

+2θ)+cos(120

∘

−2θ))

=1+sin

2

θ−

2

1

(2cos120

∘

cos2θ)

=1+sin

2

θ+

2

1

(1−2sin

2

θ)

=1+

2

1

=

2

3