Question

show that : sin theta /1-cos theta + tan theta / cos theta +1 = sec theta cosec theta + cot theta ​

Answer 1

Step-by-step explanation:

sinA/1-cosA+tanA/1+cosA

=sinA/1-cosA+sinA/cosA(1+cosA)

=sinAcosA(1+cosA)+sinA(1-cosA)/ cosA(1-cos²A)

=sinAcosA+sinAcos²A+sinA-sinAcosA/ cosAsin²A

=(sinAcos²A+sinA)/cosAsin²A

=sinAcos²A/cosAsin²A+sinA/cosAsin²A

=cosA/sinA+1/cosAsinA

=cotA+secAcosecA