Question

show that sin theta by 1 + cos theta + 1 + cos theta by sin theta is equal to 2 cosec theta​

Answer 1

$\huge\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}$

Answer in attachment:

FORMULAS USED:

$\large\red{(a+b) ^{2}=a^{2}+b^{2}+2ab}$

$\large\green{sin^{2}\theta+cos^{2}\theta=1}$

$\large\purple{sin\theta=\dfrac{1}{cosec\theta}}$