Show that (sin theta +cos theta)^2– (sin theta – cos theta )^2= 2 sin 2theta
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Answer:
Step-by-step explanation:
LHS= (sinθ+cosθ)²– (sinθ-cosθ )²
=>sin²θ+cos²θ+2sinθcosθ-sin²θ-cos²θ+2sinθcosθ
=>2×2×sinθcosθ (2×sinθcosθ=sin2θ )
=>2sin2θ = RHS
Hence prove
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