Show that (sin theta + cos theta) whole square + (cos theta + secant theta) whole square equals to 7 + tan square theta + cot square theta
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Step-by-step explanation:
(sin theta + cos theta) ^2= 1+2 sin.cos
( cos theta + sec theta) ^2= cos^2 theta+ sec^2 theta + 2
so, 1+2 sin. cos+cos^2 theta+sec^2 theta + 2
=3+sin.cos + cos^4 theta +1/ cos^2 theta
=
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