Question

show that (sin0+cos π/6)(sin π/6+tan π/4)/tan π/6+cot π/3)(sec π/3-cosec π/2)=9/8

Answer 1

Step-by-step explanation:

$(0 + \frac{ \sqrt{3} }{2} )( \frac{ 1}{2} + 1)( \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{3} } )(2 - 1) \\ = \frac{ \sqrt{3} }{2} \times \frac{3}{2} \times \frac{2}{ \sqrt{3} } \\ = \frac{3}{2}$

Answer 2

Answer:

$(0 + \frac{ \sqrt{3} }{2})( \frac{1}{2} + 1)( \frac{1}{ \sqrt{3 } } + \frac{1}{ \sqrt{3} } )(2 - 1) \\ \\ = = > \: \frac{ \sqrt{3} }{2} \times \frac{3}{2} \times \frac{2}{ \sqrt{3} } \\ \\ = = > \: \frac{3}{2}$

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