show that sin105°+cos105°=cos45°
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Answer:
sin105
o
+cos105
0
sin(60
0
+45
)+cos(60
+45
) ∵sin(A
0
+B
= sinA cosB+ cosAsinB ,cos(A
0
+B
= cosA cosB− sinAsinB
=cos45
[sin60
+cos60
+cos60
−sin60
=cos45
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