Math, asked by krishpatel02613, 6 months ago

show that sin2 35+ sin2 55 - tan2 45 =0​

Answers

Answered by soumyadiproy894
0

Step-by-step explanation:

sin^2 35° + sin^2 55° - tan^2 45°

= (cos^2 55° + sin^2 55°) - tan^2 45°

= 1- tan^2 45°

= 1-1= 0( Proved)

I hope this answer will help you......

Answered by gumnaambadshah
1

Answer:

A helicopter is ascending with a velocity of 2 m/s at a height of 24 m when it drops a mail packet. The packet contains material, which can be damaged if it hits ground with velocity of magnitude greater than 72 km / h. Was the packet damaged? Explain your answer.

(Take g = 10 m/s2)

Ans

As the packet reaches the ground with a velocity (22 m/s) greate

Ans

As the packet reaches the ground with a velocity (22 m/s) greater than the safe velocity of 20 m/s, so it is damaged.A helicopter is ascending with a velocity of 2 m/s at a height of 24 m when it drops a mail packet. The packet contains material, which can be damaged if it hits ground with velocity of magnitude greater than 72 km / h. Was the packet damaged? Explain your answer.

(Take g = 10 m/s2)

Ans

As the packet reaches the ground with a velocity (22 m/s) greate

Ans

As the packet reaches the ground with a velocity (22 m/s) greater than the safe velocity of 20 m/s, so it is damaged.A helicopter is ascending with a velocity of 2 m/s at a height of 24 m when it drops a mail packet. The packet contains material, which can be damaged if it hits ground with velocity of magnitude greater than 72 km / h. Was the packet damaged? Explain your answer.

(Take g = 10 m/s2)

Ans

As the packet reaches the ground with a velocity (22 m/s) greate

Ans

As the packet reaches the ground with a velocity (22 m/s) greater than the safe velocity of 20 m/s, so it is damaged.

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