show that sin2 x=2 sinx .cosx
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Proofs of Trigonometric Identities I, sin 2x = 2sin x cos x. That's all it takes. It's a simple proof, really.
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sin(x+x)
sinx.cosx+cosx.sinx
sinx(cosx+cosx)
sinx. 2cosx
2sinx.cosx
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