Show that sin28 degree = cos 62degree Hint: use sin 90- theeta=cos teeta
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Answered by
1
sin(90-A)=cosA
where A is angle
so
sin(90-62)=cos62
sin28=cos62
where A is angle
so
sin(90-62)=cos62
sin28=cos62
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0
here is your answer.
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