show that sin28°=cos62°(Hint:Use sin(90°-thita°)
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2
sin28
=sin(90-62)
=cos62
=sin(90-62)
=cos62
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sin 28°=sin(90-61)
so as we know sin(90-theta)=cos theta
it is equal to cos61°
so as we know sin(90-theta)=cos theta
it is equal to cos61°
msairam1:
please tell me that there is 62 or 61
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