show that sin2a/1+cos2a=tana
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L.H.S.
=sin2a/(1+cos2a)
=2sina×cosa/(1+cos²a-sin²a)
=2sina×cosa/(cos²a+sin²a+cos²a-sin²a)
=2sina×cosa/(2cos²a)
=sina/cosa
=tana
=R.H.S.
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