Math, asked by devaray, 8 months ago

Show that sin3A/sinA = 4 cos 2A

Answers

Answered by chandana647

1

Answer:

L.H.S=sin3A/sinA=3sinA-4sin*3A/sinA

=3-4sin*2A

= 3-4(1-cos*2A)

3-4+4cos*2A

=-1+4 cos *2A

R.H.S=4 cos 2A

=4(2cos*2A-1)

I Think the question is wrong

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