show that sin³theta + cos³theta/sin theta + cos theta =1-sin theta cos theta
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=( sin^3 A + cos^3A )/(sinA + cosA)
= (sinA + cosA)^3 - 3sinAcosA(sinA+cosA)
--------:---:-------. ----------------------------------
(sinA + cosA). (sinA + cosA)
= (sinA + cosA)^2 - 3sinAcosA
= sin^2A + cos^2A + 2sinAcosA - 3sinAcosA
= 1 - sinAcosA
RHS proved
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