show that sin600 Cos330 + cos 120 sin 150 =-1
Answers
Answered by
2
Answer:
sin 600° cos 330° + cos 120° sin 150°
= sin(360° + 240°) cos(360° – 30°) + cos(90° + 30°) sin(180° – 30°)
= sin 240° cos 30° – sin 30° sin 30°
= sin(270° – 30°) cos 30° – (1/2)(1/2)
= -cos 30° cos 30° – (1/4)
= -(√3/2)(√3/2) – (1/4)
= -(3/4) – (1/4)
= -4/4
= -1
hope it's helpful to you
Similar questions