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[sinA/(1+cosA )]+ [(1 + cosA)/sinA] =2cosecA
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(2 + 2cosA)/sinA(1 + cosA) = 2(1 + cosA)/sinA(1 + cosA) = 2/sinA = 2 cosecA [since 1/sinA = cosecA] = R.H.S.. Proved.
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