Show that: sinA/sin(90° - A) + cosA/cos(90° - A) = secAcosecA
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Here is your answer
Show that : sinA/sin(90° - A) + cosA/cos(90° - A) = SecA cosecA
Solution:
Taking left hand side
SinA/Sin(90-A) + CosA/Cos(90-A)
= SinA/CosA + CosA/ SinA
= Sin^2A + Cos^2A/CosA SinA
= 1/CosA SinA {Since Sin^2A +Cos^2A=1}
= 1/CosA.1/SinA
= SecA CosecA.
{Proved}
Hope it helps you friend
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Here is your answer
Show that : sinA/sin(90° - A) + cosA/cos(90° - A) = SecA cosecA
Solution:
Taking left hand side
SinA/Sin(90-A) + CosA/Cos(90-A)
= SinA/CosA + CosA/ SinA
= Sin^2A + Cos^2A/CosA SinA
= 1/CosA SinA {Since Sin^2A +Cos^2A=1}
= 1/CosA.1/SinA
= SecA CosecA.
{Proved}
Hope it helps you friend
Please Mark as brainliset
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