Question

show that spare of any positive integer is in the form of 4m+1 for some integer m ?

Answer 1

Answer:

Step-by-step explanation:

The question must be to prove square of any odd integer is of the form 4m + 1

now,

Let any odd no. be (2n+1)

⇒(2n+1)² = 4n² + 4n + 1

= 4(n²+n) + 1

= 4m + 1       [m = n² + n]