show that square of an odd integer is of the Form 8 q + 1 for some positive integer q
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b=4
when r=1
a= 4q+1
Squaring both sides
a^2= (4q+1)^2
a^2=16q^2+8q+1
a^2=8(2q^2+1)+1
a^2=8q+1. where q= 2q^2+1
when r=1
a= 4q+1
Squaring both sides
a^2= (4q+1)^2
a^2=16q^2+8q+1
a^2=8(2q^2+1)+1
a^2=8q+1. where q= 2q^2+1
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