Show that square of an odd positive integer is of the form 8m 1, for some integer m
Answers
Answered by
5
Answer:
Hey friend
Step-by-step explanation:
Let us consider an odd positive no.
1
1²=8*0+1=1
3
3²=8*1+1=9
7
7²=8*6+1=49
11
11²=8*15+1=121 and so on.
So,here in each case you can see that
Every square of odd positive integer can be written in the form 8m+1 where m be any positive integer.
Hence proved
Hope it will help you
Answered by
1
Answer:
let 'a' be any positive integer
a = 4q +1
squaring both sides
(a)²= (4q+1)²
a² = (4q)² + (1)² + 2(4q)(1)
a² = 16q² + 1 + 8q
a²=8(2q²+q) +1
here (2q²+q) = m
then
a²= 8m +1
hence proved
Step-by-step explanation:
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