Math, asked by 6283, 7 months ago

show that square of an odd positive integer is of the form 8m +1 ,for some integer m

Answers

Answered by RishiAEC
2

Answer:

= 8( 8m²+ 14m + 6 ) + 1 . = 8q + 1 . [ Where q = 8m² + 14m + 6 ] . Hence, the square of any odd positive integer is of the form 8q + 1 .

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