show that square of an odd positive integer is of the form 8n+1 where n is any Integer....
please answer.......
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example:all odd natural numbers.
A=BQ+R
LET THE FORM =
8n +1
when R=0 then A =8n
R=1 then A=8n +1
A=(8n+1)^2
A=64n^2+1+16n
a= 64n^2 +16n +1
a= 8n (8n+2)+1
so now it is in the form of 8n+1 for all odd numbers don't forget about the square
A=BQ+R
LET THE FORM =
8n +1
when R=0 then A =8n
R=1 then A=8n +1
A=(8n+1)^2
A=64n^2+1+16n
a= 64n^2 +16n +1
a= 8n (8n+2)+1
so now it is in the form of 8n+1 for all odd numbers don't forget about the square
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