Show that square of any positive integer is of the form 4m
Answers
Answered by
3
Hey friend your answer is ☺
here we take 2q
According to question
(2q) ²=4q²
here q²=m
4m
here we take 2q
According to question
(2q) ²=4q²
here q²=m
4m
lulucaty799p76y1q:
Thanks alot
Answered by
1
Let's say X is a positive integer.
. Then it will be either 4k, 4k+1 ,4k+2,4k+3
Let's do for 1st case.
X^2= 4k+1
Squaring both sides
X^4= (4k+1)^2
=16k^2+1+8k=16*(4m+1)+8k+1=64m+8k+17=4(16m+2k+4)+1
Similarly for others
. Then it will be either 4k, 4k+1 ,4k+2,4k+3
Let's do for 1st case.
X^2= 4k+1
Squaring both sides
X^4= (4k+1)^2
=16k^2+1+8k=16*(4m+1)+8k+1=64m+8k+17=4(16m+2k+4)+1
Similarly for others
Similar questions