show that square of odd positive integer is in the form of 8q+1 for integer q
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Here is the answer to your question.
Any odd positive integer is of the form 4q + 1 or 4q + 3 for some integer q.
I'm using here 8m+1
At the place of 8q+1
When n = 4q + 1,
Hence, square of any positive odd integer is of the form 8m + 1, for some integer m.
Any odd positive integer is of the form 4q + 1 or 4q + 3 for some integer q.
I'm using here 8m+1
At the place of 8q+1
When n = 4q + 1,
Hence, square of any positive odd integer is of the form 8m + 1, for some integer m.
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yashkumar:
thank you
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