Question

show that [square root of 2+3 square root of 8]^2 = 98

Answer 1

Answer:

$( \sqrt{2} + 3 \sqrt{8} ) {}^{2} = ( \sqrt{2} + 6 \sqrt{2} ) {}^{2} =$

$(7 \sqrt{2} ) {}^{2} = 49 \times 2 = 98$