Math, asked by shammiassadi6, 2 months ago

show that sum of an ap whose 1st term is a, second term is b and last term is c is equal to Sn=(a+c)(b+c-2a)÷2(b-a)​

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Answered by prajwalchaudhari
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Answer:

show that sum of an ap whose 1st term is a, second term is b and last term is c is equal to Sn=(a+c)(b+c-2a)÷2(b-a)

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