Question

Show that sum of any 2 sides of triangle is greater than 3rd side

Answer 1

Answer:

Given ΔABC, extend BA to D such that AD = AC.

Now in ΔDBC

∠ADC = ∠ACD [Angles opposite to equal sides are equal]

Hence ∠BCD > ∠ BDC

That is BD > BC [The side opposite to the larger (greater) angle is longer]

Þ AB + AD > BC  

∴ AB + AC > BC [Since AD = AC)

Thus sum of two sides of a triangle is always greater than third side.

Answer 2

Answer:

Step-by-step explanation:

If one side of a triangle is 6

Other is 8

Then the third will be more than 14

If it is less than it the triangle cant be made