Math, asked by lisa9683, 9 months ago

show that sum of multiples of 3 between 1 and 100 is 1683.​

Answers

Answered by poojadevi01011974
3

Step-by-step explanation:

3,6,9,12,....99

an = a+(n-1)d

99 = 3+(n-1)3

33 = 3n-3

36= 3n

n= 12

sn= n/2(a+an)

sn= 6(3+99)

sn=612ans

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