show that sum of multiples of 3 between 1 and 100 is 1683.
Answers
Answered by
3
Step-by-step explanation:
3,6,9,12,....99
an = a+(n-1)d
99 = 3+(n-1)3
33 = 3n-3
36= 3n
n= 12
sn= n/2(a+an)
sn= 6(3+99)
sn=612ans
Similar questions