Show that sum of rational with an irrational is always irrational.
Answers
Answered by
0
yes because the sum of rational with an irrational is always irrational
halasadeeq:
Just answer if u know or atleast let others answer
Answered by
4
Assume that a is rational, b is irrational, and a + b is rational. Since a and a + b are rational, we can write them as fractions.
Let a = c/d and a + b = m/n
Plugging a = c/d into a + b = m/n gives the following:
c/d + b = m/n
Now, let's subtract c/d from both sides of the equation.
b = m/n - c/d, or
b = m/n + (-c/d)
Since the rational numbers are closed under addition, b = m/n + (-c/d) is a rational number. However, the assumptions said that b is irrational, and b cannot be both rational and irrational. This is our contradiction, so it must be the case that the sum of a rational and an irrational number is irrational.
And that's our proof!
hope it help
Let a = c/d and a + b = m/n
Plugging a = c/d into a + b = m/n gives the following:
c/d + b = m/n
Now, let's subtract c/d from both sides of the equation.
b = m/n - c/d, or
b = m/n + (-c/d)
Since the rational numbers are closed under addition, b = m/n + (-c/d) is a rational number. However, the assumptions said that b is irrational, and b cannot be both rational and irrational. This is our contradiction, so it must be the case that the sum of a rational and an irrational number is irrational.
And that's our proof!
hope it help
Similar questions
Math,
6 months ago