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tan 3x tan 2x tan x= tan 3x- tan 2x- tanx
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tan2x = tan(3x-x)
= (tan3x - tanx)/(1+tan3x tanx)
=>tan3x - tanx = tan2x(1+tan3x tanx)-----(1)
now,
put the value of eq. (1) in RHS of ques.
then,
tan2x(1+tan3x tanx)- tan2x
= tanx tan2x tan3x = LHS
Step-by-step explanation:
hence, proved
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