Question

show that tan 48' tan 16 tan42 tan 74=1
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Answer 1

Answer:

given:-

LHS=tan 48 tan 16 tan42 tan 74

tan48 tan16 tan(90-42) tan(90-74)

tan48 tan16 cot48 cot16 (since tan(90-Ø) = cotØ)

tan48cot48 tan16cot16

1×1 (since tanØcotØ = 1)

1 = RHS

Hence proved