show that : tan 48 .tan 23 .tan 42 .tan 67 = 1
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Answer:
please refer the following attachment
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Step-by-step explanation:
We know that, TanA=Cot(90-A)
Here let us convert Tan48 into Cot =Cot42 --------------------- 1
Also,
Convert Tan 63 into Cot = Cot27 --------------------------------2
put values of 1 and 2 in original equation
⇒ Cot42 . Tan23 . Cot23 . Tan 42 = 1
We also know, TanA . CotA =1
Therefore,
Cot42.Tan42 = 1
and, Tan23.Cot23 = 1
So, in original/given equation
⇒ 1 .1 = 1
⇒ 1
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