Question

Show that tan^4A + tan^2A = sec^4A- sec^2A.

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Answer 1

Step-by-step explanation:

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Answer 2

${tan}^{4} A + {tan}^{2} A \\ \\ = {tan}^{2} A( {tan}^{2}A + 1) \\ \\ = {tan}^{2} A {sec}^{2} A \\ \\ = ( {sec}^{2} A - 1) {sec}^{2} A \\ \\ = {sec}^{4} A - {sec}^{2} A$