Question

show that (tan A ×sin A)+cos A=sec A​

Answer 1

Answer:

sinA+cosA=1

1/secA .-secA

0=0

Step-by-step explanation:

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Answer 2

Answer:

${ \tan( \alpha ) \times \sin( \alpha ) } \: + \cos( \alpha )$

$\sin( \alpha ) \ / \cos( \alpha ) \ × sin( \alpha ) + \cos( \alpha )$

${ \sin( \alpha ) }^{2} / \cos( \alpha ) + \cos( \alpha )$

${ \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} / \cos( \alpha )$

$1 \ / \ \cos( \alpha )$

$\sec( \alpha )$