Question

show that tan'A-sin'A=tan'A.sin'A​

Answer 1

Answer:

Prove that: tanA+sinAtanA−sinA=secA+1secA−1

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Text Solution

Solution :

L.H.S.=tanA+sinAtanA−sinA

=sinAcosA+sinAsinAcosA−cosA=sinAsinA[secA+1][secA−1]

=R.H.S