show that tan'A-sin'A=tan'A.sin'A
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Answer:
Prove that: tanA+sinAtanA−sinA=secA+1secA−1
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Text Solution
Solution :
L.H.S.=tanA+sinAtanA−sinA
=sinAcosA+sinAsinAcosA−cosA=sinAsinA[secA+1][secA−1]
=R.H.S
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