Question

Show that tan α +tan α = secα -sec .α

Answer 1

Answer:

$tan \: a + tan \: b = \frac{sin \: a}{cos \: a} + \frac{sin \: b}{cos \: b}$

$= \frac{sin \: a.cos \: b + cos \: a.sin \: b}{cos \: a \: .cos \: b}$